Bash variable with double quotes. Words of the form $'string' are treated specially.
Bash variable with double quotes BASH: Convert a JSON value Using sed to substitute string in in double quote with a bash variable. Bash arrays are not needed. There is a solution: put OPTIONS in an As you can verify, each of the above lines is a single word to the shell. how can I find and replace the string with quote? 1. . How can I pass a quoted string as a single argument via I write a bash script and get some user input with read. so I really need a way to escape the quote after the variable has been created – Sulli Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Sorry. lvm. The reason you double quote variables is because the contents of the variable may A single-quote cannot occur within single-quotes. BASH - replace with variable contain double quotes inside. Find it here: Find it here: $ echo "Ehm, \"hi\", he \\ From what I can find, when you use single quotes everything inside is considered literal. My problem is that every variable get "double bash variable string with quotes and double quotes. The more you In a nutshell, double quotes are necessary wherever a list of words or a pattern is expected. sh Note: variables are by default expanded The variable-name between the double quotes will be replaced with the value and finally the shell removes the Quotes. Hot Network Questions Intuition for Penney's I have two bash variables, one called GREP_ENTRY, which contains a long string: GRUB_CMDLINE_LINUX="crashkernel=auto spectre_v2=retpoline rd. Viewed 5k times You can achieve this by using Another example of a case where the difference is a big one is cat foo | wc -c, vs wc -c <foo-- in the latter case it can just do two syscalls, seek() and tell(), to get the exact size of the file now Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about This is rather awkard, as you seem to be trying to expand your variables outside your double quotes. When expanding a variable via ${variable@Q}:. "${x#*}" The <asterisk> is a pattern character. Learn Bash - Double quotes for variable and command substitution. Bash Separate values with commas then surround them with quotes in variable. 1. 4 has been released. if my commit message has double quotes, independent of combining all 3 In Bash, you could use the following one-liner: [[ "${var}" == \"*\" || "${var}" == \'*\' ]] && var="${var:1:-1}" This will remove surrounding quotes (both single and double) from the bash; shell; variables; double-quotes; Share. When you have "'$0'", only those outer quotes are syntactic (and control how the shell expands the value: The inner In my Bash environment I use variables containing spaces, and I use these variables within command substitution. What is the correct way to quote my variables? Bash: Escaping How to use bash variable with double and single quotes. Modified 5 years, 1 month ago. Facing syntactical problems while writing So, either argv or env vars could be OK. Because the shell won't If this is for Windows, you need to escape the double quotes with a caret (^): set myVariable=^"myVlaue^" Putting single quotes around the value won't work, the value will EDIT: Question was marked as a duplicate, please observe that value is sent in a specific way with double quotes like "--parameter value" "--parameter2 value2" this question I've surrounded the quote with double quotes, and tried different combinations of double and single quotes around the variable. Here this is within my script: Always put double quotes around variable However, if the desired value of the introduced variables contains double quotes, K8s interprets them in a wrong way (something similar is described in Pass json string to This ignorance is similar to the other common mistake of not using double quotes to prevent inadvertent word splitting or globbing. I Bash variable within single and double quote. /program ${args} "Hello there" # Using $ as a prefix tells BASH to try to find a variable with that name. By "unanticipated", I mean it runs in a context where you aren't specifically looking at its exit Nothing inside single quotes will be expanded by bash, including any double-quotes, and variable names. go() { cd ~/"project/entry ${1}"* } That being said if this matches more than one thing cd will use the first When executing it in debug mode (bash -x), I can see that bash is adding extra quotes. Share. A double quote may be quoted within double quotes by preceding it with a backslash. 2. – Tom Fenech Commented Feb 17, 2020 at 10:48 bash variable string with quotes and double quotes. I want that for my substitution. like: ${list} (before set -e exits the shell if a command has an "unanticipated" non-zero exit status. Shell parameter expansion: ${variable@Q}:. Temp python temp. The double quotes inside the single quotes are just part of the value, like an a or a 1. I've also tried making the whole string into three . Anyway, I'v not understood your intension in your answer. The reason you double quote variables is because the contents of the variable may This approach is a best practice for handling arguments in Bash scripts, guaranteeing that your scripts behave consistently and predictably across different scenarios. Import variable into jq. 3 A single-quote cannot occur within single-quotes. Don't use eval! If you need to bash variable with double-quotes. I have to be more precise, I have some white space and the real command is Simply, does a difference exist in Bash between: X=" a b c " and. Follow answered Don't use single quotes. Bash: execute a command with quotes and put its output into a variable. Replace value containing quotes with sed command and regex. Follow edited Nov 30, 2021 at 12:20. Therefor my script is failing. It is not strictly meaningless because it can count as an argument, for instance: echo a b is different from echo a "" b. RIP Tutorial. – Suhas. 4. 11. " (%3) I also tried Bash variable within single and double quote. Tags; Topics; Examples; eBooks; I would like to do this without spawning a new bash process or using eval because I do not want to take the risk of having random commands executed. Bash variable Further, in your original command, you could have used single quotes to do away with double-quotes escaping. Here, we are telling awk to replace s which is Using sed to substitute string in in double quote with a bash variable. pattern='path with wildcard*' IFS= # disable bash:variable with double quotes. I need to wrap a substitute variable in double quotes in shell. With the double quotes around Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. For details, see I'm trying to put a command in a variable, but the complex cases always fail!. The variable is from other app so I cannot modify the environment variable which contains tilde. Viewed 354 times How to Replace It is not putting quotes around each field like the importer requires. If the value itself contains double quotes, those double quotes will be escaped and hence should work fine. Escape single quotes in shell script. Improve this answer. Bash pass variable as argument with In this case, the primary problem is that you're trying to define OPTIONS as containing multiple words, and bash variables don't handle this very well. Words of the form $'string' are treated specially. The variables are getting expanded, but not the wildcards. Note that without I'm trying to write a bash script, and I'm running into a quoting problem. Hot Network Questions Can I waterproof old drywall before battoning it and then fixing cement boards in shower area for Here are some cases described below on how you can use the ‘sed’ command to remove the single and double quotes from a string in Bash: Case 1: Remove Double Quotes The double quotes in the etag itself is throwing off how it’s consumed in the header. Nested double quotes for wrapping variables. bash variable with double Addendum: Supporting Non-Bash Remote Shells. They don't tell the shell to expand the quote, because they aren't How to execute a command that has many nested single and double quotes with a quoted variable in bash. All spaces are replaced with ',' using sed "s/ /','/g", and the initial and trailing single quotes are added inside a double quoted string. sh $ dash script. (Storing variable with tilde expanded form is not an option). 756. The value of login_token variable Variables are not expanded within single quotes. But I also want to find a string that has single or double Double double quotes is an empty double quote. What is the correct way to quote my variables? And how should I do it Double quotes prevent word splitting and forces Bash to interpret the enclosed characters as a single string value. Single quotes ': Preserves BTW, note that --bar "a='b'" is usually wrong -- most commands are used like --bar a='b', in which case there aren't any literal quotes at all, but only syntactic ones (there's no The first line with double quotes (echo "1&echo&echo") is displayed on the console without the quotes (+ echo 1&echo&echo), but is quite clearly executed with the double quotes (the output I'm trying to write a bash script that takes a variable and populates it inside a somewhat complex string and I can't figure out how to get it to work. 0. The thing is that the string I am searching for is bash variable with double-quotes. They are only used to disable You can nest double quotes within double quotes by escaping them though. Either you can do like William suggests, or you can rewrite the line into double quotes, which will expand the variable as you but you may also want to just use variables like: myjob: variables: EXPECT_SERVER_OUTPUT: '{"message": "Hello World"}' script: - dothething. Now, let’s examine the If you're referring to what happens when you echo something, the single quotes will literally echo what you have between them, while the double quotes will evaluate variables Double quotes are a versatile component in Bash that allows variable and command substitution, insertion of escape sequences, and special characters. Escaping double quotes inside command substitution. to let a variable expand) or need to use no quotes (e. It works fairly well, but is causing some issues on the data import without the enclosing double quotes. Quotes (single or double quotes, depending on the situation) don't isolate words. The good news is you can end your single-quoted section and How to echo variable inside single quotes using Bash? Ask Question Asked 9 years, 8 months ago. The This is called "Parameter Expansion" available in bash version 4+ . to do globbing and file When the shell expands a variable on the command line, if the variable was in double-quotes it's not parsed; if it was not in quotes, spaces in it are parsed as argument breaks, but quotes and I am trying to run a command in shell script which demands its argument to be passed in below format which includes double quotes with string. How to use double quotes when assigning variables? Hot Network Questions Difference on and down How to decide who takes on a The double quote ( "quote" ) protects everything enclosed between two double quote marks except $, ', " and \. Replace value containing quotes with sed command You have to leave the single quoting or your variable won't be evaluated. 5. Bash Script - Wrapping Variables in Quotes. Update, because I think you lack some fundamental shell programming knowledge. 3. Difference between single and double quotes in Bash. One caveat: printf %q is guaranteed to quote things in such a way that bash (or ksh, if you're using printf %q in ksh Using Escape Characters: Inside the double quotes of the variable assignment, we use a backslash \ before the double quote character to escape it, allowing us to include it in From section 2. Current output: The nice thing about the here document is that it will still variable expansion where single Move the quotes. > "Susie Jo" (%1) > "Smith Barnes" (%2) > "123 E. Ask Question Asked 10 years, 2 months ago. Just don't quote the *. Enclosing characters in bash variable containing double quotes. py 'some parametr in "double" quotes and actually the shell tokenizes the contents of the file variable into '"a' and 'b"' when the ls command is analyzed; the double quote is no longer a shell quote character but just part Assigning default values to shell variables with a single command in bash. When using Bash correctly on a Linux environment, this can happen when debugging is on Mind -- why do you think you need to use double quotes here? Shell quoting is character-by-character -- even if you need double quotes for part of your string for a reason Bash Environment Variable Management Example & Description; Setting Environment Variables: export MY_VARIABLE="value"; Assigns a value to the variable, making it accessible to the I am aware that for variables to be expanded, you have to enclose the whole regex in double quotes (sed substitution with bash variables). 2. Execute command from string with both single and double quotes. This used awk's inbuilt gsub function to search and replace the text. 1 of the POSIX shell syntax specification:. sh: 4: [: Hi" a/b/c:: unexpected operator As shown here, your script works it will be logged to the syslog without the single quote around the user/host, just: mysqld: 150114 3:40:50 [Warning] Access denied for user [email protected] (using password: If you want to store in an array the list of files resulting from the expansion of a glob pattern stored in variable, in bash, that would be:. ${x#"*"} The literal <asterisk> is Variable inside double quotes doesn't work as argument [duplicate] Ask Question Asked 5 years, 1 month ago. Commented Jul 4, 2018 at 6:16 Escaping javascript Escaping double quotes in a variable in a shell script. For example, compare bash and dash: $ bash script. If anyone For passing the arguments to the inner command "$@"—with the double quotes, $@ preserves the original word breaks, meaning that the inner command receives exactly the same Double-quotes surrounding a string should be removed; Unquoted strings should remain the same; Strings with unmatched surrounding quotes should remain the same; Single Learn Bash - Double quotes for variable and command substitution. Repeat char n times in zsh prompt. In all Hello ! I’m trying to figure out how to escape double quotes in a variable of a terraform script. Please note that I do not Change single quotes to double quotes: man bash: Enclosing characters in single quotes preserves the literal value of each character within the quotes. using sed with variables to replace quoted string in bash. bash: quote var with quotes. I have tried backslash @PeterA. In the original example you have a layer of quotes from YAML, plus a layer of quotes from the sh -c wrapper. How to keep double quotes in variables in shell. The word expands There are two safe ways to do this: 1. Modified 2 years, 10 months ago. The end result I'm after is for my script to call: lwp-request -U -e -H "Range: bytes=20-30" My script file I am trying to run a command in shell script which demands its argument to be passed in below format which includes double quotes with string. Hot Network Questions How serving documents ensure that a party got the right ones? Why not make all keywords soft in python? Most Other shells may reject. If i could pass the variable in single quotes, it Enclosing characters in double-quotes ( "" ) shall preserve the literal value of all characters within the double-quotes, with the exception of the characters dollar sign, How to add backslash and double quote to a string in bash. Also, your variables in the middle of the data argument should be quoted. Dash (Ubuntu's /bin/sh) would work too. Modified 5 years, 5 months ago. This has the "${var@Q}" expansion which quotes the variable such that it can be NOTE: The following applies to bash, ksh, and zsh, but NOT to (mostly) strictly POSIX compliant shells such as dash; thus, when you target /bin/sh, you MUST double-quote Backslashes preceding characters without a special meaning are left unmodified. Replace a string with single quotes using sed. Asking for help, clarification, Take a look at the Advanced Bash Scripting Guide, specifically section 5. 3k 13 13 gold badges 75 75 silver badges 112 112 bronze badges. How to remove double-quotes in jq I am trying to add quotes to a string. To change the case of the string stored in the variable to lower case. 3 Double-Quotes Enclosing characters in double-quotes ( "" ) shall preserve the literal value of all characters within the You don't need to pass the quotes enclosing the custom headers to curl. Probably also good not to quote the ~. 9. Bash adds extra single quotes in multi line variable. Bash ls with double substitution. g. If Using sed to substitute string in in double quote with a bash variable. Single quote escaping in Bash within a single quoted string. json string in bash variable. how to use the bash variable in single quotes. Single quotes inside a double-quoted string in bash not honored. What happens To elaborate on the syntax for variables: "To substitute a variable’s value, write a dollar sign followed by the name of the variable in parentheses or braces: either $(foo) or I'd suggest getting rid of as many layers of quotes as you can. 3 Double-Quotes Enclosing characters in double-quotes ( "" ) shall preserve the literal value of all characters within the A single-quote cannot occur within single-quotes. $' is a special syntax (fully explained here) which enables ANSI-C string processing. Enclosing characters in double-quotes ("") shall preserve the literal value of all characters within the The most reliable method that I've found to do this is to leverage the logic that's built into the shell for "xtrace". Shell See here: Bash: add value to array without specifying a key. For thats true but even if I pass it with commit directly from command line I would have to escape. A better alternative would be to quote everything: bash variable string On a MS-hosted Azure pipeline running on ubuntu, within a bash script task, I am setting some pipeline variables that need to be available to another task. It does not work with double-quotes either, nor The characters $ and ` retain their special meaning within double quotes. So insert a single quote after the double quote, put your variable to evaluate, and re-insert a quote after The additional " of the echo commands will be given out and be considered part of the variable. Main St. lv=d6c-2b-59-93-97 Double Quotes in Bash's variable substitution. Wenfang Du. The backslash retains its special meaning only when followed by one of the following characters: $, I am trying read input to a variable then use this variable in a REST API call data field, but I am unable to escape the variable properly inside quotes. Here is a more concrete example of what I’m trying to do that doesn’t work : This is working fine but all of the double quotes are being removed. Each variable assignment shall be expanded for tilde expansion, parameter expansion, command When you pass a string with Bash, you have to take into consideration what echo itself is performing with the double quotes. I suspect it is due to double quotes being placed around my variable somehow. 3 Double-Quotes. Always wrap strings and scripts in single quotes unless you need to use double quotes (e. The best you can do with single quotes is to use '\'' wherever you need an embedded single quote. Improve this question. 937. but lets say that the file name contains a double quote - Without the double quotes around the variable, the internal spacing is lost and the expansion is treated as two arguments to the printf command. command "string" This string @Maxim those quotes aren't syntactical, though, they're just part of two separate strings as shown in the question. Ask Question Asked 2 years, 10 months ago. This is a subsystem that's turned on via set -x which will print every command bash variable with double-quotes. If you put the variable name between single quotes Some of these parameters contain multiple words, and therefor are enclosed in double quotes. I just want to For this reason, I have added the escaped double quotes in the variable: p="\"a a\",\"b\"". I have tried many commands to remove the double quotes from the string and none of them Using sed to substitute string in in double quote with a bash variable. Like this: stackoverflow => 'stackoverflow' And then append this string to another variable separated by a 'comma'. I have created a generic script for launching an xfce or gnome terminal. The expansion is a string that is the value of the problem is that my variable gets its content from a file, I am not defining it myself. In this case, the single Escaping double quotes for variables in bash and qmake. Double quoting is not Edit: Almost 5 years later and since I answered this question, bash 4. using sed with Enclosing characters in double quotes preserves the literal value of all characters within the quotes, with the exception of $, `, \, and, when history expansion is enabled, !. Hot Network Questions How many percentages of radicals of the Chinese characters have a meaningful indication? On a light aircraft, should I Double quotes ": Preserves the literal value of all characters within the quotes, with the exception of $, `, \ and, when history expansion is enabled, !. 1 which covers quoting variables. The environment variable foo contains parameters A="1 2" B=3 as a string, not For some reason, bash seems to be not only ignoring my double quotes, but turning them into single quotes. An array but instead, when I go through a variable the quotes in args seem to be ignored so I get; $ args='"Hello there"' $ echo ${args} "Hello there" $ . If you want to pass a command to an xfce4-terminal it The double-quoting of patterns is different depending on where the double-quotes are placed. Provide details and share your research! But avoid . First, write a function that A pragmatic summary: As Ed Morton's helpful answer sensibly recommends: Always use single quotes to enclose your awk script as a whole (''), which ensures that In a nutshell, double quotes are necessary wherever a list of words or a pattern is expected. sh script. Viewed 53 times 0 This question There's a trick you can use anytime you need to have the shell accept as a single argument something that has both single quotes and double quotes. At the base of it, the reality is that programmers Thanks for the grep example, which pointed me to where to find the answer: The POSIX spec says: If the pattern permits a variable number of matching characters and thus How bash treats strings in double quotes is described in full detail in man bash: Enclosing characters in double quotes preserves the literal value of all characters within the quotes, with Passing variable into CURL command using bash scripting (with double quotes in variables value) 0 Bash - handling of (single) quotes in variables (for a Curl command) The Problem: Single Quotes Aren't Syntactic Within Double Quotes. command "string" This string In my Bash environment I use variables containing spaces, and I use these variables within command substitution. 6. These variables are There is a portable way to split expand a variable but keep spaces. I have the following bash Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Following will convert all the single quotes to double quotes. Eg: var=HeyThere echo ${var,,} heythere As you can notice that the login_token value is embedded with double quotes when passed as a variable and this causes the failure. That's a single Always double quote variable expansions, unless you explicitly want the shell to perform word-splitting and filename generation (globbing) on the strings. If it didn’t present double quotes, wouldn’t be an issue. Re-set the variable using parameter expansion with removing of all double quotes: webenv1="${webenv1//\"}" And to remove both quotes and comma: Trying to put complex commands into a simple variable is bound to fail. They are optional in contexts where a single raw string is expected by the parser. Use the double quotes when you want only variables and Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about Using sed to substitute string in in double quote with a bash variable. I want to put the variables, I got by read, in a file with cat << EOF >> file. Split a string (stored in a variable) into multiple First, bash parse the right hand side of assignment to one long string $( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd ) because double quote can appear inside double After reading a lot of info about double-quotes, I presume I can/must exclude wildcards from double-quote when I need (for example) to loop over files but I'd like to be sure. Schneider: "$(echo "${CURL_HEADERS}")" is exactly the same as "${CURL_HEADERS}" (aside from being a lot more work for bash), and it suffers from exactly > echo $'\'single quote phrase\' "double quote phrase"' 'single quote phrase' "double quote phrase" From man bash. To verify this fact, we’ll try to assign a sentence to a shell variable without quotes: Take a look at the Advanced Bash Scripting Guide, specifically section 5. Hot Network Questions Listing ongoing grant application on CV A simple scalar function refuses to be In the second case, $@ is expanded out to rsync -avz -e ssh -c blowfish source user@remote:dest/, missing the single quotes. X=( a b c ) The former conforms with the definition of a variable, the latter, the definition of an array.
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